7m^2+49=56m

Solution for 7m^2+49=56m equation:

7m^2+49=56m

We move all terms to the left:

7m^2+49-(56m)=0

a = 7; b = -56; c = +49;
Δ = b2-4ac
Δ = -562-4·7·49
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-42}{2*7}=\frac{14}{14}
=1
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+42}{2*7}=\frac{98}{14}
=7
$